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a^2=25/121
We move all terms to the left:
a^2-(25/121)=0
We add all the numbers together, and all the variables
a^2-(+25/121)=0
We get rid of parentheses
a^2-25/121=0
We multiply all the terms by the denominator
a^2*121-25=0
Wy multiply elements
121a^2-25=0
a = 121; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·121·(-25)
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12100}=110$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-110}{2*121}=\frac{-110}{242} =-5/11 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+110}{2*121}=\frac{110}{242} =5/11 $
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